Using the same argument as before it becomes clear that the number on the gate is 13, and the ages 9, 2 and 2. Therefore, when told that one child is the eldest, the census-taker concludes that the correct solution is 'B'. In case 'A', there is no 'eldest child': two children are aged six (although one could be a few minutes or around 9 to 12 months older and they still both be 6). Only two sets of possible ages add up to the same totals: This gives the following triplets of possible solutions īecause the census taker knew the total (from the number on the gate) but said that he had insufficient information to give a definitive answer, there must be more than one solution with the same total. 15 college credits and 1 to 3 high school credits (taking a combination of.
#RIDDLE SCHOOL 3 COMBINATION REGISTRATION#
The prime factors of 72 are 2, 2, 2, 3, 3 in other words, 2 × 2 × 2 × 3 × 3 = 72 Riddle Elementary School will hold registration from August 10 through August. their ages adding up to today's date, or the eldest being good at chess ).Īnother version of the puzzle gives the age product as thirty–six, which leads to a different set of ages for the children. The problem can be presented in different ways, giving the same basic information: the product, that the sum is known, and that there is an oldest child (e.g. After school jesse went to andrew's locker and pulled the paper. The woman enters her house, but before slamming the door tells the census taker, "I have to see to my eldest child who is in bed with measles." The census taker departs, satisfied. Combination lock riddle apa combination for a lock has 3 wheels, x, y, and z, each of which can be set to eight different positions. The sum of their ages is the number on this gate." The census taker does some calculation and claims not to have enough information. She says, "I have three children and the product of their ages is seventy–two. A census taker approaches a woman leaning on her gate and asks about her children.